What is the general solution for sec(2θ)=2,0<θ< pi/2 ?

The general solution for sec(2θ)=2,0<θ< pi/2 is θ= pi/6

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sec(2θ)=2,0<θ< pi/2

sec (2 θ) = 2, 0 < θ < \frac{π}{2}

θ = \frac{π}{6}

Solution steps

sec (2 θ) = 2, 0 < θ < \frac{π}{2}

General solutions for

sec (2 θ) = 2

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{5 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{5 π}{3} + 2 πn : θ = \frac{5 π}{6} + πn

θ = \frac{π}{6} + πn, θ = \frac{5 π}{6} + πn

Solutions for the range

0 < θ < \frac{π}{2}

θ = \frac{π}{6}

2 cos (2 θ) + 1 = 0

sec (\frac{5 θ}{4}) = 2

sin^{2} (x) = 1 - cos (x)

3 sec (x) - 4 cos (x) = 0

arctan (x) = \frac{π}{2}

What is the general solution for sec(2θ)=2,0<θ< pi/2 ?
The general solution for sec(2θ)=2,0<θ< pi/2 is θ= pi/6