What is the general solution for cos(2θ)+sin^2(θ)=0 ?

The general solution for cos(2θ)+sin^2(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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cos(2θ)+sin^2(θ)=0

cos (2 θ) + sin^{2} (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

cos (2 θ) + sin^{2} (θ) = 0

Rewrite using trig identities

cos^{2} (θ) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

tan^{2} (x) + tan (x) = 0, 0 \leq x < 2 π

csc (x) - 1 = 0

cos (2 x) + 5 cos (x) + 3 = 0

2 cos (θ) = 1

sin (x + \frac{π}{6}) - sin (x - \frac{π}{6}) = \frac{1}{2}

What is the general solution for cos(2θ)+sin^2(θ)=0 ?
The general solution for cos(2θ)+sin^2(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin