What is the general solution for tan^2(θ)-1=0 ?

The general solution for tan^2(θ)-1=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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tan^2(θ)-1=0

tan^{2} (θ) - 1 = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

tan^{2} (θ) - 1 = 0

Solve by substitution

tan (θ) = 1, tan (θ) = - 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

tan (x) - 2 sin (x) tan (x) = 0

cos (x) = \frac{2}{5}

sin (θ) + cos (θ) = 2

sin^{2} (x) - cos^{2} (x) = \frac{1}{2}

2 sin^{2} (x) + cos (x) = 0

What is the general solution for tan^2(θ)-1=0 ?
The general solution for tan^2(θ)-1=0 is θ= pi/4+pin,θ=(3pi)/4+pin