What is the general solution for sin(x+pi/4)+sin(x-pi/4)=-1 ?

The general solution for sin(x+pi/4)+sin(x-pi/4)=-1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x+pi/4)+sin(x-pi/4)=-1

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) = - 1

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) = - 1

Rewrite using trig identities

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

cos (\frac{x}{4}) = 0

cos (θ) = 0.92

2 sin (2 x) = 1

2 cos (x) = 2

sin (θ) - 1 = 0

What is the general solution for sin(x+pi/4)+sin(x-pi/4)=-1 ?
The general solution for sin(x+pi/4)+sin(x-pi/4)=-1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin