What is the general solution for (tan(θ)+1)(sec(θ)-1)=0 ?

The general solution for (tan(θ)+1)(sec(θ)-1)=0 is θ=(3pi)/4+pin,θ=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(tan(θ)+1)(sec(θ)-1)=0

(tan (θ) + 1) (sec (θ) - 1) = 0

θ = \frac{3 π}{4} + πn, θ = 2 πn

Solution steps

(tan (θ) + 1) (sec (θ) - 1) = 0

Solving each part separately

tan (θ) + 1 = 0 or sec (θ) - 1 = 0

tan (θ) + 1 = 0 : θ = \frac{3 π}{4} + πn

sec (θ) - 1 = 0 : θ = 2 πn

Combine all the solutions

θ = \frac{3 π}{4} + πn, θ = 2 πn

sin (x) = - \frac{3}{5}

2 tan (x) cos (x) - tan (x) = 0

sin (\frac{x}{2}) = 2 - sin (\frac{x}{2})

tan (3 x) = \frac{3}{3}

sin (x) tan (x) = sin (x)

What is the general solution for (tan(θ)+1)(sec(θ)-1)=0 ?
The general solution for (tan(θ)+1)(sec(θ)-1)=0 is θ=(3pi)/4+pin,θ=2pin