What is the general solution for cos(x+pi/6)-cos(x-pi/6)=1 ?

The general solution for cos(x+pi/6)-cos(x-pi/6)=1 is x=(3pi)/2+2pin

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cos(x+pi/6)-cos(x-pi/6)=1

cos (x + \frac{π}{6}) - cos (x - \frac{π}{6}) = 1

x = \frac{3 π}{2} + 2 πn

Solution steps

cos (x + \frac{π}{6}) - cos (x - \frac{π}{6}) = 1

Rewrite using trig identities

- sin (x) = 1

Divide both sides by

- 1

sin (x) = - 1

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πn

tan (2 θ) + 2 sin (θ) = 0

2 cos^{2} (x) + 7 sin (x) = 5

tan^{2} (x) + sec (x) = 1

- 4 sin (2 x) = 0

\frac{sin ( 2 x )}{cos ( x )} = 2

What is the general solution for cos(x+pi/6)-cos(x-pi/6)=1 ?
The general solution for cos(x+pi/6)-cos(x-pi/6)=1 is x=(3pi)/2+2pin