What is the general solution for 3sqrt(2)cos(θ)+2=-1 ?

The general solution for 3sqrt(2)cos(θ)+2=-1 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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3sqrt(2)cos(θ)+2=-1

32 cos (θ) + 2 = - 1

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

32 cos (θ) + 2 = - 1

Move

2

to the right side

32 cos (θ) = - 3

Divide both sides by

32

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

sin (x) cos (x) = \frac{3}{4}

2 cos^{2} (x) = 3 sin (x)

sin (2 x) + 2 cos (x) = 0

2 sin (x) + cos (2 x) = 1

2 sin (2 x) = 0

What is the general solution for 3sqrt(2)cos(θ)+2=-1 ?
The general solution for 3sqrt(2)cos(θ)+2=-1 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin