What is the general solution for cos(θ)=-5/13 ?

The general solution for cos(θ)=-5/13 is θ=1.96558…+2pin,θ=-1.96558…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=-5/13

cos (θ) = - \frac{5}{13}

θ = 1.96558 \dots + 2 πn, θ = - 1.96558 \dots + 2 πn

Solution steps

cos (θ) = - \frac{5}{13}

Apply trig inverse properties

θ = arccos (- \frac{5}{13}) + 2 πn, θ = - arccos (- \frac{5}{13}) + 2 πn

Show solutions in decimal form

θ = 1.96558 \dots + 2 πn, θ = - 1.96558 \dots + 2 πn

4 sec (θ) + 6 = - 2

- 2 sin (x) + cos (2 x) \cdot 2 = 0

sec^{2} (x) - 2 = tan^{2} (x)

4 tan^{2} (x) - 1 = tan^{2} (x)

tan (θ) sin (θ) + sin (θ) = 0

What is the general solution for cos(θ)=-5/13 ?
The general solution for cos(θ)=-5/13 is θ=1.96558…+2pin,θ=-1.96558…+2pin