What is the general solution for sqrt(3)sin(x)=cos(x) ?

The general solution for sqrt(3)sin(x)=cos(x) is x= pi/6+pin

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sqrt(3)sin(x)=cos(x)

3 sin (x) = cos (x)

x = \frac{π}{6} + πn

Degrees

x = 3 0^{\circ} + 18 0^{\circ} n

Solution steps

3 sin (x) = cos (x)

Rewrite using trig identities

3 sin (x) = cos (x)

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{3 sin ( x )}{cos ( x )} = \frac{cos ( x )}{cos ( x )}

Simplify

\frac{3 sin ( x )}{cos ( x )} = 1

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

3 tan (x) = 1

3 tan (x) = 1

Divide both sides by

3

3 tan (x) = 1

Divide both sides by

3

\frac{3 tan ( x )}{3} = \frac{1}{3}

Simplify

\frac{3 tan ( x )}{3} = \frac{1}{3}

Simplify

\frac{3 tan ( x )}{3} : tan (x)

\frac{3 tan ( x )}{3}

Cancel the common factor:

3

= tan (x)

Simplify

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

General solutions for

tan (x) = \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{6} + πn

x = \frac{π}{6} + πn

sec^{2} (x) - 3 sec (x) = 0

3 cot (x) + 1 = 0

tan (x) = - \frac{2}{3}

tan (θ) = \frac{5}{3}

tan (x) = \frac{3}{5}

What is the general solution for sqrt(3)sin(x)=cos(x) ?
The general solution for sqrt(3)sin(x)=cos(x) is x= pi/6+pin