What is the general solution for 4cos(2t)+1=3 ?

The general solution for 4cos(2t)+1=3 is t= pi/6+pin,t=(5pi)/6+pin

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4cos(2t)+1=3

4 cos (2 t) + 1 = 3

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

Solution steps

4 cos (2 t) + 1 = 3

Move

1

to the right side

4 cos (2 t) = 2

Divide both sides by

4

cos (2 t) = \frac{1}{2}

General solutions for

cos (2 t) = \frac{1}{2}

2 t = \frac{π}{3} + 2 πn, 2 t = \frac{5 π}{3} + 2 πn

Solve

2 t = \frac{π}{3} + 2 πn : t = \frac{π}{6} + πn

Solve

2 t = \frac{5 π}{3} + 2 πn : t = \frac{5 π}{6} + πn

t = \frac{π}{6} + πn, t = \frac{5 π}{6} + πn

cos (2 x) - cos (x) = - 1

cos (x + \frac{π}{4}) - cos (x - \frac{π}{4}) = 1

y, x = cos (y)

cot (x) cos^{2} (x) = 2 cot (x)

tan (θ) = 4

What is the general solution for 4cos(2t)+1=3 ?
The general solution for 4cos(2t)+1=3 is t= pi/6+pin,t=(5pi)/6+pin