What is the general solution for 2sin(θ)=sqrt(2) ?

The general solution for 2sin(θ)=sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin

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2sin(θ)=sqrt(2)

2 sin (θ) = 2

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Solution steps

2 sin (θ) = 2

Divide both sides by

2

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

5 cos (x) - 3 = 3 cos (x)

tan (x) + 3 = 0

2 sin (x) - 1 = 0

tan (x) = \frac{5}{3}

cos (\frac{x}{2}) \frac{1}{2} = 0

What is the general solution for 2sin(θ)=sqrt(2) ?
The general solution for 2sin(θ)=sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin