What is the general solution for 2sin(θ)=-sqrt(2) ?

The general solution for 2sin(θ)=-sqrt(2) is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin

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2sin(θ)=-sqrt(2)

2 sin (θ) = - 2

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

2 sin (θ) = - 2

Divide both sides by

2

sin (θ) = - \frac{2}{2}

General solutions for

sin (θ) = - \frac{2}{2}

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

3 cot (t) - 1 = 0

2 cos^{2} (x) + 3 sin (x) = 3

x, y = cos (x)

sin (6 x) = 0

sin (x) = 3

What is the general solution for 2sin(θ)=-sqrt(2) ?
The general solution for 2sin(θ)=-sqrt(2) is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin