What is the general solution for 2cos(θ)=-1 ?

The general solution for 2cos(θ)=-1 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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2cos(θ)=-1

2 cos (θ) = - 1

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

2 cos (θ) = - 1

Divide both sides by

2

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin (θ) = \frac{2}{5}

cos (2 x) - cos (x) = 0, 0 \leq x \leq 2 π

cos (θ) = 2

sin (2 x) - tan (x) = 0

cos (4 x) - 1 = 0

What is the general solution for 2cos(θ)=-1 ?
The general solution for 2cos(θ)=-1 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin