What is the general solution for cos(2x)-cos(6x)=0 ?

The general solution for cos(2x)-cos(6x)=0 is x=pin,x= pi/2+pin,x=(pin)/2 ,x= pi/4+(pin)/2

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cos(2x)-cos(6x)=0

cos (2 x) - cos (6 x) = 0

x = πn, x = \frac{π}{2} + πn, x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

cos (2 x) - cos (6 x) = 0

Rewrite using trig identities

2 sin (2 x) sin (4 x) = 0

Solving each part separately

sin (2 x) = 0 or sin (4 x) = 0

sin (2 x) = 0 : x = πn, x = \frac{π}{2} + πn

sin (4 x) = 0 : x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Combine all the solutions

x = πn, x = \frac{π}{2} + πn, x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

cot^{2} (θ) = \frac{3}{2} csc (θ)

cos (t) = \frac{1}{2}

cos (x) = 2

6 cos^{2} (x) - 7 sin (x) - 1 = 0

2 sin^{2} (θ) + 3 sin (θ) + 1 = 0

What is the general solution for cos(2x)-cos(6x)=0 ?
The general solution for cos(2x)-cos(6x)=0 is x=pin,x= pi/2+pin,x=(pin)/2 ,x= pi/4+(pin)/2