What is the general solution for sin(θ)+cos(θ)=1 ?

The general solution for sin(θ)+cos(θ)=1 is θ=2pin,θ=2pin+pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)+cos(θ)=1

sin (θ) + cos (θ) = 1

θ = 2 πn, θ = 2 πn + \frac{π}{2}

Solution steps

sin (θ) + cos (θ) = 1

Rewrite using trig identities

2 sin (θ + \frac{π}{4}) = 1

Divide both sides by

2

sin (θ + \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (θ + \frac{π}{4}) = \frac{2}{2}

θ + \frac{π}{4} = \frac{π}{4} + 2 πn, θ + \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

θ + \frac{π}{4} = \frac{π}{4} + 2 πn : θ = 2 πn

Solve

θ + \frac{π}{4} = \frac{3 π}{4} + 2 πn : θ = 2 πn + \frac{π}{2}

θ = 2 πn, θ = 2 πn + \frac{π}{2}

cos (x^{2}) = 0

sec^{2} (x) = 2 sec (x)

sin (x) = \frac{2}{5}

cos (\frac{θ}{2}) = \frac{3}{2}

cos (x) = 0.3

What is the general solution for sin(θ)+cos(θ)=1 ?
The general solution for sin(θ)+cos(θ)=1 is θ=2pin,θ=2pin+pi/2