What is the general solution for 2sin(θ)+4=3 ?

The general solution for 2sin(θ)+4=3 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(θ)+4=3

2 sin (θ) + 4 = 3

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (θ) + 4 = 3

Move

4

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

sin^{2} (x) - sin (x) = cos^{2} (x)

tan (θ) = - \frac{3}{4}

cos (x) = 3 cos (x) - 2

4 cos (x) = 1 + 2 cos (x)

2 sin (x) + 1 = csc (x)

What is the general solution for 2sin(θ)+4=3 ?
The general solution for 2sin(θ)+4=3 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin