What is the general solution for sin(2θ)=cos(2θ) ?

The general solution for sin(2θ)=cos(2θ) is θ= pi/8+(pin)/2

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sin(2θ)=cos(2θ)

sin (2 θ) = cos (2 θ)

θ = \frac{π}{8} + \frac{πn}{2}

Solution steps

sin (2 θ) = cos (2 θ)

Rewrite using trig identities

tan (2 θ) = 1

General solutions for

tan (2 θ) = 1

2 θ = \frac{π}{4} + πn

Solve

2 θ = \frac{π}{4} + πn : θ = \frac{π}{8} + \frac{πn}{2}

θ = \frac{π}{8} + \frac{πn}{2}

cosh (z) = 0

cos (x) = \frac{2}{π}

tan^{2} (x) + 3 tan (x) + 1 = 0

csc (2 x) = 2, 0 \leq x < 2 π

sin (x) + cos (x) = 1.2

What is the general solution for sin(2θ)=cos(2θ) ?
The general solution for sin(2θ)=cos(2θ) is θ= pi/8+(pin)/2