What is the general solution for cos(x+(3pi)/4)-cos(x-(3pi)/4)=1 ?

The general solution for cos(x+(3pi)/4)-cos(x-(3pi)/4)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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cos(x+(3pi)/4)-cos(x-(3pi)/4)=1

cos (x + \frac{3 π}{4}) - cos (x - \frac{3 π}{4}) = 1

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

cos (x + \frac{3 π}{4}) - cos (x - \frac{3 π}{4}) = 1

Rewrite using trig identities

- 2 sin (x) = 1

Divide both sides by

- 2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

tan (2 θ) + 2 cos (θ) = 0

2 cos^{2} (x) + 9 sin (x) = 6

cot (2 x) = 0

cos (2 x) = cos^{2} (x)

tan (\frac{x}{2}) = \frac{3}{3}

What is the general solution for cos(x+(3pi)/4)-cos(x-(3pi)/4)=1 ?
The general solution for cos(x+(3pi)/4)-cos(x-(3pi)/4)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin