What is the general solution for 25cot^2(θ)-16=0 ?

The general solution for 25cot^2(θ)-16=0 is θ=0.89605…+pin,θ=2.24553…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25cot^2(θ)-16=0

25 cot^{2} (θ) - 16 = 0

θ = 0.89605 \dots + πn, θ = 2.24553 \dots + πn

Solution steps

25 cot^{2} (θ) - 16 = 0

Solve by substitution

cot (θ) = \frac{4}{5}, cot (θ) = - \frac{4}{5}

cot (θ) = \frac{4}{5} : θ = arccot (\frac{4}{5}) + πn

cot (θ) = - \frac{4}{5} : θ = arccot (- \frac{4}{5}) + πn

Combine all the solutions

θ = arccot (\frac{4}{5}) + πn, θ = arccot (- \frac{4}{5}) + πn

Show solutions in decimal form

θ = 0.89605 \dots + πn, θ = 2.24553 \dots + πn

2 sin^{2} (x) = sin (x) + 1

sin (3 x) = - \frac{3}{2}

3 sin (2 x) sin (x) = 3 cos (x)

3 sin (x) + csc (x) = 0

cos (x) = \frac{4}{7}

What is the general solution for 25cot^2(θ)-16=0 ?
The general solution for 25cot^2(θ)-16=0 is θ=0.89605…+pin,θ=2.24553…+pin