What is the general solution for -4sin(4x)=0 ?

The general solution for -4sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4sin(4x)=0

- 4 sin (4 x) = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

- 4 sin (4 x) = 0

Divide both sides by

- 4

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

cos (x) = - 3

2 cos (3 θ) = 1

sin^{2} (x) + sin (x) - 1 = 0

2 cos^{2} (x) = 2 - sin (x)

sin (θ) = - \frac{1}{2}

What is the general solution for -4sin(4x)=0 ?
The general solution for -4sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2