What is the general solution for 2cos^2(t)=1-cos(t) ?

The general solution for 2cos^2(t)=1-cos(t) is t= pi/3+2pin,t=(5pi)/3+2pin,t=pi+2pin

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2cos^2(t)=1-cos(t)

2 cos^{2} (t) = 1 - cos (t)

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn, t = π + 2 πn

Solution steps

2 cos^{2} (t) = 1 - cos (t)

Solve by substitution

cos (t) = \frac{1}{2}, cos (t) = - 1

cos (t) = \frac{1}{2} : t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

cos (t) = - 1 : t = π + 2 πn

Combine all the solutions

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn, t = π + 2 πn

sec^{2} (θ) + sec (θ) = 0

cos (2 x) - 3 cos (x) + 2 = 0

2 cos (θ) + 3 = 2

sin (2 x + \frac{π}{6}) = \frac{1}{2}

csc (5 x) = - 1

What is the general solution for 2cos^2(t)=1-cos(t) ?
The general solution for 2cos^2(t)=1-cos(t) is t= pi/3+2pin,t=(5pi)/3+2pin,t=pi+2pin