What is the general solution for (tan(θ)+1)(sec(θ)+1)=0 ?

The general solution for (tan(θ)+1)(sec(θ)+1)=0 is θ=(3pi)/4+pin,θ=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(tan(θ)+1)(sec(θ)+1)=0

(tan (θ) + 1) (sec (θ) + 1) = 0

θ = \frac{3 π}{4} + πn, θ = π + 2 πn

Solution steps

(tan (θ) + 1) (sec (θ) + 1) = 0

Solving each part separately

tan (θ) + 1 = 0 or sec (θ) + 1 = 0

tan (θ) + 1 = 0 : θ = \frac{3 π}{4} + πn

sec (θ) + 1 = 0 : θ = π + 2 πn

Combine all the solutions

θ = \frac{3 π}{4} + πn, θ = π + 2 πn

2 sin (θ) - tan^{2} (θ) = 0

sin (θ) - 3 cos (θ) = 1

cos (a) = \frac{1}{2}

cos^{2} (θ) = \frac{3}{4}

tan (θ) = \frac{3}{8}

What is the general solution for (tan(θ)+1)(sec(θ)+1)=0 ?
The general solution for (tan(θ)+1)(sec(θ)+1)=0 is θ=(3pi)/4+pin,θ=pi+2pin