What is the general solution for cos(θ)=0.98 ?

The general solution for cos(θ)=0.98 is θ=0.20033…+2pin,θ=2pi-0.20033…+2pin

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cos(θ)=0.98

cos (θ) = 0.98

θ = 0.20033 \dots + 2 πn, θ = 2 π - 0.20033 \dots + 2 πn

Solution steps

cos (θ) = 0.98

Apply trig inverse properties

θ = arccos (0.98) + 2 πn, θ = 2 π - arccos (0.98) + 2 πn

Show solutions in decimal form

θ = 0.20033 \dots + 2 πn, θ = 2 π - 0.20033 \dots + 2 πn

sec^{2} (x) = 3 tan^{2} (x) - 1

csc (x) + cot (x) = \frac{3}{3}

sin (θ) + 1 = cos (θ)

2 sin^{2} (θ) - sin (θ) = 0

2 sin^{2} (x) = 2 - 3 cos (x)

What is the general solution for cos(θ)=0.98 ?
The general solution for cos(θ)=0.98 is θ=0.20033…+2pin,θ=2pi-0.20033…+2pin