What is the general solution for cos((2x-pi)/6)=((sqrt(3)))/2 ,0<x<2pi ?

The general solution for cos((2x-pi)/6)=((sqrt(3)))/2 ,0<x<2pi is x=pi

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cos((2x-pi)/6)=((sqrt(3)))/2 ,0<x<2pi

cos (\frac{2 x - π}{6}) = \frac{( 3 )}{2}, 0 < x < 2 π

x = π

Solution steps

cos (\frac{2 x - π}{6}) = \frac{( 3 )}{2}, 0 < x < 2 π

General solutions for

cos (\frac{2 x - π}{6}) = \frac{3}{2}

\frac{2 x - π}{6} = \frac{π}{6} + 2 πn, \frac{2 x - π}{6} = \frac{11 π}{6} + 2 πn

Solve

\frac{2 x - π}{6} = \frac{π}{6} + 2 πn : x = π + 6 πn

Solve

\frac{2 x - π}{6} = \frac{11 π}{6} + 2 πn : x = 6 π + 6 πn

x = π + 6 πn, x = 6 π + 6 πn

Solutions for the range

0 < x < 2 π

x = π

4 sin (\frac{t}{2}) - 1 = 1

2 cos^{2} (x) = sin (2 x)

tan (θ) + cot (θ) = 4 sin (2 θ)

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0

sin (x) = 0, 0 \leq x \leq 2 π

What is the general solution for cos((2x-pi)/6)=((sqrt(3)))/2 ,0<x<2pi ?
The general solution for cos((2x-pi)/6)=((sqrt(3)))/2 ,0<x<2pi is x=pi