What is the general solution for 0=sin(2x) ?

The general solution for 0=sin(2x) is x=pin,x= pi/2+pin

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0=sin(2x)

0 = sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = sin (2 x)

Switch sides

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

2 cos^{2} (x) - 3 cos (x) - 2 = 0

sin (2 x) csc (2 x) - 2 sin (2 x) = 0

2 sin^{3} (x) + sin^{2} (x) - 2 sin (x) - 1 = 0

5 cos^{2} (θ) + cos (θ) = 0

x, z = sin (x y)

What is the general solution for 0=sin(2x) ?
The general solution for 0=sin(2x) is x=pin,x= pi/2+pin