What is the general solution for sin(2x-pi/4)=(sqrt(2))/2 ?

The general solution for sin(2x-pi/4)=(sqrt(2))/2 is x= pi/4+pin,x=pin+pi/2

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sin(2x-pi/4)=(sqrt(2))/2

sin (2 x - \frac{π}{4}) = \frac{2}{2}

x = \frac{π}{4} + πn, x = πn + \frac{π}{2}

Solution steps

sin (2 x - \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (2 x - \frac{π}{4}) = \frac{2}{2}

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn, 2 x - \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

2 x - \frac{π}{4} = \frac{π}{4} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x - \frac{π}{4} = \frac{3 π}{4} + 2 πn : x = πn + \frac{π}{2}

x = \frac{π}{4} + πn, x = πn + \frac{π}{2}

tan (2 x) = cot (x)

cos (x) = 0.7

2 - 2 cos^{2} (x) = sin (x) + 1

sin (x) = - \frac{1}{4}

sin (x) + cos (2 x) = 0

What is the general solution for sin(2x-pi/4)=(sqrt(2))/2 ?
The general solution for sin(2x-pi/4)=(sqrt(2))/2 is x= pi/4+pin,x=pin+pi/2