What is the general solution for 2cos(x/5)-sqrt(2)=0 ?

The general solution for 2cos(x/5)-sqrt(2)=0 is x=(5pi)/4+10pin,x=(35pi)/4+10pin

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2cos(x/5)-sqrt(2)=0

Solution

2 cos (\frac{x}{5}) - 2 = 0

Solution

x = \frac{5 π}{4} + 10 πn, x = \frac{35 π}{4} + 10 πn

Degrees

x = 22 5^{\circ} + 180 0^{\circ} n, x = 157 5^{\circ} + 180 0^{\circ} n

Solution steps

2 cos (\frac{x}{5}) - 2 = 0

Move

2

to the right side

2 cos (\frac{x}{5}) - 2 = 0

Add

2

to both sides

2 cos (\frac{x}{5}) - 2 + 2 = 0 + 2

Simplify

2 cos (\frac{x}{5}) = 2

2 cos (\frac{x}{5}) = 2

Divide both sides by

2

2 cos (\frac{x}{5}) = 2

Divide both sides by

2

\frac{2 cos ( \frac{x}{5} )}{2} = \frac{2}{2}

Simplify

cos (\frac{x}{5}) = \frac{2}{2}

cos (\frac{x}{5}) = \frac{2}{2}

General solutions for

cos (\frac{x}{5}) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{x}{5} = \frac{π}{4} + 2 πn, \frac{x}{5} = \frac{7 π}{4} + 2 πn

\frac{x}{5} = \frac{π}{4} + 2 πn, \frac{x}{5} = \frac{7 π}{4} + 2 πn

Solve

\frac{x}{5} = \frac{π}{4} + 2 πn : x = \frac{5 π}{4} + 10 πn

\frac{x}{5} = \frac{π}{4} + 2 πn

Multiply both sides by

5

\frac{x}{5} = \frac{π}{4} + 2 πn

Multiply both sides by

5

\frac{5 x}{5} = 5 \cdot \frac{π}{4} + 5 \cdot 2 πn

Simplify

\frac{5 x}{5} = 5 \cdot \frac{π}{4} + 5 \cdot 2 πn

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

5 \cdot \frac{π}{4} + 5 \cdot 2 πn : \frac{5 π}{4} + 10 πn

5 \cdot \frac{π}{4} + 5 \cdot 2 πn

Multiply

5 \cdot \frac{π}{4} : \frac{5 π}{4}

5 \cdot \frac{π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 5}{4}

= \frac{5 π}{4} + 5 \cdot 2 πn

Multiply the numbers:

5 \cdot 2 = 10

= \frac{5 π}{4} + 10 πn

x = \frac{5 π}{4} + 10 πn

x = \frac{5 π}{4} + 10 πn

x = \frac{5 π}{4} + 10 πn

Solve

\frac{x}{5} = \frac{7 π}{4} + 2 πn : x = \frac{35 π}{4} + 10 πn

\frac{x}{5} = \frac{7 π}{4} + 2 πn

Multiply both sides by

5

\frac{x}{5} = \frac{7 π}{4} + 2 πn

Multiply both sides by

5

\frac{5 x}{5} = 5 \cdot \frac{7 π}{4} + 5 \cdot 2 πn

Simplify

\frac{5 x}{5} = 5 \cdot \frac{7 π}{4} + 5 \cdot 2 πn

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

5 \cdot \frac{7 π}{4} + 5 \cdot 2 πn : \frac{35 π}{4} + 10 πn

5 \cdot \frac{7 π}{4} + 5 \cdot 2 πn

5 \cdot \frac{7 π}{4} = \frac{35 π}{4}

5 \cdot \frac{7 π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 π 5}{4}

Multiply the numbers:

7 \cdot 5 = 35

= \frac{35 π}{4}

5 \cdot 2 πn = 10 πn

5 \cdot 2 πn

Multiply the numbers:

5 \cdot 2 = 10

= 10 πn

= \frac{35 π}{4} + 10 πn

x = \frac{35 π}{4} + 10 πn

x = \frac{35 π}{4} + 10 πn

x = \frac{35 π}{4} + 10 πn

x = \frac{5 π}{4} + 10 πn, x = \frac{35 π}{4} + 10 πn

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Frequently Asked Questions (FAQ)

What is the general solution for 2cos(x/5)-sqrt(2)=0 ?
The general solution for 2cos(x/5)-sqrt(2)=0 is x=(5pi)/4+10pin,x=(35pi)/4+10pin