What is the general solution for sin^2(θ)-2sin(θ)=0 ?

The general solution for sin^2(θ)-2sin(θ)=0 is θ=2pin,θ=pi+2pin

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sin^2(θ)-2sin(θ)=0

sin^{2} (θ) - 2 sin (θ) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

sin^{2} (θ) - 2 sin (θ) = 0

Solve by substitution

sin (θ) = 2, sin (θ) = 0

sin (θ) = 2 :

No Solution

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

sin^{2} (x) + cos (x) = 0

3 sec^{2} (x) - 5 = 4 tan (x)

4 tan^{2} (x) + 5 tan (x) = 6

cos (2 x) = \frac{1}{3}

2 sin^{2} (x) - 5 sin (x) + 3 = 0

What is the general solution for sin^2(θ)-2sin(θ)=0 ?
The general solution for sin^2(θ)-2sin(θ)=0 is θ=2pin,θ=pi+2pin