What is the general solution for sin(z)=0 ?

The general solution for sin(z)=0 is z=2pin,z=pi+2pin

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sin(z)=0

sin (z) = 0

z = 2 πn, z = π + 2 πn

Solution steps

sin (z) = 0

General solutions for

sin (z) = 0

z = 0 + 2 πn, z = π + 2 πn

Solve

z = 0 + 2 πn : z = 2 πn

z = 2 πn, z = π + 2 πn

4 sec (x) + 4 tan (x) = 4

8 sin (2 x) sin (x) = 8 cos (x)

cos (x) = - \frac{3}{4}

2 cos^{2} (x) + cos (x) - 1 = 0, 0 \leq x \leq 2 π

arcsin (x) - arccos (- \frac{1}{2}) = \frac{π}{6}

What is the general solution for sin(z)=0 ?
The general solution for sin(z)=0 is z=2pin,z=pi+2pin