What is the general solution for sin(2x)-(sqrt(3))/2 =0 ?

The general solution for sin(2x)-(sqrt(3))/2 =0 is x= pi/6+pin,x= pi/3+pin

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sin(2x)-(sqrt(3))/2 =0

sin (2 x) - \frac{3}{2} = 0

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

Solution steps

sin (2 x) - \frac{3}{2} = 0

Move

\frac{3}{2}

to the right side

sin (2 x) = \frac{3}{2}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{2 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

csc^{2} (θ) - 4 = 0

sin (3 x) + cos (3 x) = - \frac{2}{2}

cos (θ) = 0.5

cos^{2} (x) - \frac{3}{4} = 0

cos (\frac{θ}{2}) - 1 = 0

What is the general solution for sin(2x)-(sqrt(3))/2 =0 ?
The general solution for sin(2x)-(sqrt(3))/2 =0 is x= pi/6+pin,x= pi/3+pin