What is the general solution for cos(2x-pi/6)=(sqrt(3))/2 ?

The general solution for cos(2x-pi/6)=(sqrt(3))/2 is x= pi/6+pin,x=pin+pi

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cos(2x-pi/6)=(sqrt(3))/2

cos (2 x - \frac{π}{6}) = \frac{3}{2}

x = \frac{π}{6} + πn, x = πn + π

Solution steps

cos (2 x - \frac{π}{6}) = \frac{3}{2}

General solutions for

cos (2 x - \frac{π}{6}) = \frac{3}{2}

2 x - \frac{π}{6} = \frac{π}{6} + 2 πn, 2 x - \frac{π}{6} = \frac{11 π}{6} + 2 πn

Solve

2 x - \frac{π}{6} = \frac{π}{6} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x - \frac{π}{6} = \frac{11 π}{6} + 2 πn : x = πn + π

x = \frac{π}{6} + πn, x = πn + π

12 cos^{2} (θ) = 9

sin (\frac{x}{2}) - 1 = 0

sec (\frac{3 x}{2}) = - 2

cos (θ) = - \frac{4}{5}

2 sin (θ) cos (θ) + cos (θ) = 0

What is the general solution for cos(2x-pi/6)=(sqrt(3))/2 ?
The general solution for cos(2x-pi/6)=(sqrt(3))/2 is x= pi/6+pin,x=pin+pi