What is the general solution for 4sin(x)-1=2sin(x)+1 ?

The general solution for 4sin(x)-1=2sin(x)+1 is x= pi/2+2pin

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4sin(x)-1=2sin(x)+1

4 sin (x) - 1 = 2 sin (x) + 1

x = \frac{π}{2} + 2 πn

Solution steps

4 sin (x) - 1 = 2 sin (x) + 1

Solve by substitution

sin (x) = 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn

sin (3 x) = \frac{3}{4}

sin (x + \frac{π}{3}) + cos (x + \frac{π}{6}) = \frac{3}{3}

4 sin^{2} (x) cot (x) - 3 cot (x) = 0

sin (2 x) = - 2 cos^{2} (x)

cos (\frac{2 x + 3}{2}) = - \frac{1}{2}

What is the general solution for 4sin(x)-1=2sin(x)+1 ?
The general solution for 4sin(x)-1=2sin(x)+1 is x= pi/2+2pin