What is the general solution for sin(θ/2)=(sqrt(3))/2 ?

The general solution for sin(θ/2)=(sqrt(3))/2 is θ=(2pi)/3+4pin,θ=(4pi)/3+4pin

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sin(θ/2)=(sqrt(3))/2

sin (\frac{θ}{2}) = \frac{3}{2}

θ = \frac{2 π}{3} + 4 πn, θ = \frac{4 π}{3} + 4 πn

Solution steps

sin (\frac{θ}{2}) = \frac{3}{2}

General solutions for

sin (\frac{θ}{2}) = \frac{3}{2}

\frac{θ}{2} = \frac{π}{3} + 2 πn, \frac{θ}{2} = \frac{2 π}{3} + 2 πn

Solve

\frac{θ}{2} = \frac{π}{3} + 2 πn : θ = \frac{2 π}{3} + 4 πn

Solve

\frac{θ}{2} = \frac{2 π}{3} + 2 πn : θ = \frac{4 π}{3} + 4 πn

θ = \frac{2 π}{3} + 4 πn, θ = \frac{4 π}{3} + 4 πn

cos (θ) = - 2

cos (x) = - \frac{π}{3}

tan (θ) = - 2 sin (θ)

2 sin (x) = 2 cos (2 x)

4 sin (\frac{x}{2}) + 2 cos (x) = 3

What is the general solution for sin(θ/2)=(sqrt(3))/2 ?
The general solution for sin(θ/2)=(sqrt(3))/2 is θ=(2pi)/3+4pin,θ=(4pi)/3+4pin