What is the general solution for sin^2(x)+2sin(x)-3=0 ?

The general solution for sin^2(x)+2sin(x)-3=0 is x= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)+2sin(x)-3=0

sin^{2} (x) + 2 sin (x) - 3 = 0

x = \frac{π}{2} + 2 πn

Solution steps

sin^{2} (x) + 2 sin (x) - 3 = 0

Solve by substitution

sin (x) = 1, sin (x) = - 3

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 3 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

sin^{2} (x) - tan (x) cos^{2} (x) = 0

2 sin (x) cos (x) - sin (x) + 2 cos (x) - 1 = 0

sec^{2} (x) = 2 tan (x)

4 sin^{2} (x) - 8 cos (x) + 1 = 0

sec^{2} (θ) = 4

What is the general solution for sin^2(x)+2sin(x)-3=0 ?
The general solution for sin^2(x)+2sin(x)-3=0 is x= pi/2+2pin