What is the general solution for 2tan^2(θ)+5tan(θ)=0 ?

The general solution for 2tan^2(θ)+5tan(θ)=0 is θ=pin,θ=-1.19028…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2tan^2(θ)+5tan(θ)=0

2 tan^{2} (θ) + 5 tan (θ) = 0

θ = πn, θ = - 1.19028 \dots + πn

Solution steps

2 tan^{2} (θ) + 5 tan (θ) = 0

Solve by substitution

tan (θ) = 0, tan (θ) = - \frac{5}{2}

tan (θ) = 0 : θ = πn

tan (θ) = - \frac{5}{2} : θ = arctan (- \frac{5}{2}) + πn

Combine all the solutions

θ = πn, θ = arctan (- \frac{5}{2}) + πn

Show solutions in decimal form

θ = πn, θ = - 1.19028 \dots + πn

cos (θ) - 3 sin (θ) = 1

sec (x) = \frac{1}{2}

2 cos^{2} (x) = sin (x) + 1

csch (x) = \frac{5}{12}

2 sin^{2} (x) + sin (x) = 1, 0 \leq x \leq 2 π

What is the general solution for 2tan^2(θ)+5tan(θ)=0 ?
The general solution for 2tan^2(θ)+5tan(θ)=0 is θ=pin,θ=-1.19028…+pin