What is the general solution for 2cos(2x)=-sqrt(3) ?

The general solution for 2cos(2x)=-sqrt(3) is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin

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2cos(2x)=-sqrt(3)

2 cos (2 x) = - 3

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

Solution steps

2 cos (2 x) = - 3

Divide both sides by

2

cos (2 x) = - \frac{3}{2}

General solutions for

cos (2 x) = - \frac{3}{2}

2 x = \frac{5 π}{6} + 2 πn, 2 x = \frac{7 π}{6} + 2 πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

5 sec^{2} (x) - 5 sec (x) = 10

sec (x) tan (x) = \frac{2}{3}

- 1 = sin (x)

2 sin^{2} (θ) = sin (θ)

3 sin (x) = 4 cos (x)

What is the general solution for 2cos(2x)=-sqrt(3) ?
The general solution for 2cos(2x)=-sqrt(3) is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin