What is the general solution for (cot(θ)+1)(sin(θ)+1)=0 ?

The general solution for (cot(θ)+1)(sin(θ)+1)=0 is θ=(3pi)/4+pin,θ=(3pi)/2+2pin

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(cot(θ)+1)(sin(θ)+1)=0

(cot (θ) + 1) (sin (θ) + 1) = 0

θ = \frac{3 π}{4} + πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

(cot (θ) + 1) (sin (θ) + 1) = 0

Solving each part separately

cot (θ) + 1 = 0 or sin (θ) + 1 = 0

cot (θ) + 1 = 0 : θ = \frac{3 π}{4} + πn

sin (θ) + 1 = 0 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{4} + πn, θ = \frac{3 π}{2} + 2 πn

9 sec^{2} (θ) tan (θ) = 12 tan (θ)

3 tan (θ) = 1

2 cos (3 x) - 1 = 0, 0 \leq x \leq 2 π

16 cos^{2} (θ) = 4

sin (3 θ + 72) = cos (4 8^{\circ})

What is the general solution for (cot(θ)+1)(sin(θ)+1)=0 ?
The general solution for (cot(θ)+1)(sin(θ)+1)=0 is θ=(3pi)/4+pin,θ=(3pi)/2+2pin