What is the general solution for 2sin(2x)+sqrt(2)=0 ?

The general solution for 2sin(2x)+sqrt(2)=0 is x=(5pi)/8+pin,x=(7pi)/8+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(2x)+sqrt(2)=0

2 sin (2 x) + 2 = 0

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

2 sin (2 x) + 2 = 0

Move

2

to the right side

2 sin (2 x) = - 2

Divide both sides by

2

sin (2 x) = - \frac{2}{2}

General solutions for

sin (2 x) = - \frac{2}{2}

2 x = \frac{5 π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

2 cos^{2} (θ) - 3 sin (θ) + 2 = 0

sin (x) + sin (2 x) + sin (3 x) = 0

sin^{2} (x) - cos^{2} (x) = 1 + cos (x)

36 cos^{2} (x) - 9 = 0

sin (x) = \frac{5}{6}

What is the general solution for 2sin(2x)+sqrt(2)=0 ?
The general solution for 2sin(2x)+sqrt(2)=0 is x=(5pi)/8+pin,x=(7pi)/8+pin