What is the general solution for 2cos(2θ)=sqrt(3) ?

The general solution for 2cos(2θ)=sqrt(3) is θ= pi/(12)+pin,θ=(11pi)/(12)+pin

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2cos(2θ)=sqrt(3)

2 cos (2 θ) = 3

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

Solution steps

2 cos (2 θ) = 3

Divide both sides by

2

cos (2 θ) = \frac{3}{2}

General solutions for

cos (2 θ) = \frac{3}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{11 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{11 π}{6} + 2 πn : θ = \frac{11 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

2 sin^{2} (θ) - 5 sin (θ) + 2 = 0

tan (2 x) + 1 = 0

sin (x) - 2 = - sin (x)

cos (x) + 2 sin (x) = 1

8 sec (x) csc (x) = 16 csc (x)

What is the general solution for 2cos(2θ)=sqrt(3) ?
The general solution for 2cos(2θ)=sqrt(3) is θ= pi/(12)+pin,θ=(11pi)/(12)+pin