What is the general solution for cos(2θ)=(sqrt(2))/2 ?

The general solution for cos(2θ)=(sqrt(2))/2 is θ= pi/8+pin,θ=(7pi)/8+pin

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cos(2θ)=(sqrt(2))/2

cos (2 θ) = \frac{2}{2}

θ = \frac{π}{8} + πn, θ = \frac{7 π}{8} + πn

Solution steps

cos (2 θ) = \frac{2}{2}

General solutions for

cos (2 θ) = \frac{2}{2}

2 θ = \frac{π}{4} + 2 πn, 2 θ = \frac{7 π}{4} + 2 πn

Solve

2 θ = \frac{π}{4} + 2 πn : θ = \frac{π}{8} + πn

Solve

2 θ = \frac{7 π}{4} + 2 πn : θ = \frac{7 π}{8} + πn

θ = \frac{π}{8} + πn, θ = \frac{7 π}{8} + πn

4 cos (x) = 0

- \frac{1}{2} + cos^{2} (x) + cos^{2} (\frac{x}{2}) = 0

9 sin (2 x) sin (x) = 9 cos (x)

3 (1 - cos (θ)) = sin^{2} (θ)

3 tan (x) - 3 = 0

What is the general solution for cos(2θ)=(sqrt(2))/2 ?
The general solution for cos(2θ)=(sqrt(2))/2 is θ= pi/8+pin,θ=(7pi)/8+pin