What is the general solution for 1-tan^2(x)=0 ?

The general solution for 1-tan^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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1-tan^2(x)=0

1 - tan^{2} (x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

1 - tan^{2} (x) = 0

Solve by substitution

tan (x) = 1, tan (x) = - 1

tan (x) = 1 : x = \frac{π}{4} + πn

tan (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

cos (x) cos (3 x) - sin (x) sin (3 x) = 0

(cot (θ) - 1) (sin (θ) - 1) = 0

cos (2 x) = 2 sin^{2} (x)

cos (x) = - sin^{2} (x) - 1

1 + sin (x) = 3 sin (x)

What is the general solution for 1-tan^2(x)=0 ?
The general solution for 1-tan^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin