What is the general solution for 2tan^2(θ)+3tan(θ)=0 ?

The general solution for 2tan^2(θ)+3tan(θ)=0 is θ=pin,θ=-0.98279…+pin

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2tan^2(θ)+3tan(θ)=0

2 tan^{2} (θ) + 3 tan (θ) = 0

θ = πn, θ = - 0.98279 \dots + πn

Solution steps

2 tan^{2} (θ) + 3 tan (θ) = 0

Solve by substitution

tan (θ) = 0, tan (θ) = - \frac{3}{2}

tan (θ) = 0 : θ = πn

tan (θ) = - \frac{3}{2} : θ = arctan (- \frac{3}{2}) + πn

Combine all the solutions

θ = πn, θ = arctan (- \frac{3}{2}) + πn

Show solutions in decimal form

θ = πn, θ = - 0.98279 \dots + πn

tan (x) + cot (x) = 2

4 cos^{2} (x) - 4 sin (x) - 5 = 0

x, tan (x^{2} + y^{2}) = 1

2 tan (x) + sec (x) = 0

2 sin (x) cos (x) - 7 cos (x) = 0

What is the general solution for 2tan^2(θ)+3tan(θ)=0 ?
The general solution for 2tan^2(θ)+3tan(θ)=0 is θ=pin,θ=-0.98279…+pin