What is the general solution for solvefor θ,tan(θ)=1 ?

The general solution for solvefor θ,tan(θ)=1 is θ= pi/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor θ,tan(θ)=1

solve for

θ, tan (θ) = 1

θ = \frac{π}{4} + πn

Degrees

θ = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = 1

General solutions for

tan (θ) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

sec (x) csc (x) - 2 csc (x) = 0

csc (3 θ) = 6 sin (3 θ), 0 < θ < 2 π

3 tan (3 θ) - 1 = 0, 0 \leq θ \leq 2 π

(cot (θ) + 1) (csc (θ) - 1) = 0

2 sin (x) cos (x) = 1

What is the general solution for solvefor θ,tan(θ)=1 ?
The general solution for solvefor θ,tan(θ)=1 is θ= pi/4+pin