What is the general solution for 2cos(2x)+sqrt(2)=0 ?

The general solution for 2cos(2x)+sqrt(2)=0 is x=(3pi)/8+pin,x=(5pi)/8+pin

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2cos(2x)+sqrt(2)=0

2 cos (2 x) + 2 = 0

x = \frac{3 π}{8} + πn, x = \frac{5 π}{8} + πn

Solution steps

2 cos (2 x) + 2 = 0

Move

2

to the right side

2 cos (2 x) = - 2

Divide both sides by

2

cos (2 x) = - \frac{2}{2}

General solutions for

cos (2 x) = - \frac{2}{2}

2 x = \frac{3 π}{4} + 2 πn, 2 x = \frac{5 π}{4} + 2 πn

Solve

2 x = \frac{3 π}{4} + 2 πn : x = \frac{3 π}{8} + πn

Solve

2 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{8} + πn

x = \frac{3 π}{8} + πn, x = \frac{5 π}{8} + πn

5 sin (x) cos (x) = - 2 cos (x)

cos (θ) = \frac{1}{6}

2 sin (x) - 1 = csc (x)

sin^{s i n (x)} (x) = 2

4 cos (x) + 2 = 0

What is the general solution for 2cos(2x)+sqrt(2)=0 ?
The general solution for 2cos(2x)+sqrt(2)=0 is x=(3pi)/8+pin,x=(5pi)/8+pin