What is the general solution for 2sin(θ)+5=4 ?

The general solution for 2sin(θ)+5=4 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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2sin(θ)+5=4

2 sin (θ) + 5 = 4

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (θ) + 5 = 4

Move

5

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

1 - sin (x) = cos (x)

sec^{2} (x) = sec (x) + 2

(cot (θ) - 3) (2 sin (θ) + 1) = 0

5 sin (θ) - 4 = 0

x, cos (x) + cos (x + y) = 0

What is the general solution for 2sin(θ)+5=4 ?
The general solution for 2sin(θ)+5=4 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin