What is the general solution for 0=1+2sin(x) ?

The general solution for 0=1+2sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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0=1+2sin(x)

0 = 1 + 2 sin (x)

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

0 = 1 + 2 sin (x)

Switch sides

1 + 2 sin (x) = 0

Move

1

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

(cot (θ) + 1) (csc (θ) + 1) = 0

3 sec (x) csc (x) = 6 csc (x)

cos (2 x) + 6 sin^{2} (x) = 4

3 - 6 sin^{2} (x) = 0

sec^{2} (x) - 3 tan (x) = - 1

What is the general solution for 0=1+2sin(x) ?
The general solution for 0=1+2sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin