What is the general solution for 1+sin(θ)=3sin(θ) ?

The general solution for 1+sin(θ)=3sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin

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1+sin(θ)=3sin(θ)

1 + sin (θ) = 3 sin (θ)

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

1 + sin (θ) = 3 sin (θ)

Solve by substitution

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2} : θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Combine all the solutions

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

sin^{2} (x) - \frac{3}{4} = 0

tan (x) = - 8

- 3 sin (2 x) = 0

sin (x) = 0.35

tan (x) = \frac{- 1}{3}

What is the general solution for 1+sin(θ)=3sin(θ) ?
The general solution for 1+sin(θ)=3sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin