What is the general solution for 2sin(2θ)=sqrt(3) ?

The general solution for 2sin(2θ)=sqrt(3) is θ= pi/6+pin,θ= pi/3+pin

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2sin(2θ)=sqrt(3)

2 sin (2 θ) = 3

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

Solution steps

2 sin (2 θ) = 3

Divide both sides by

2

sin (2 θ) = \frac{3}{2}

General solutions for

sin (2 θ) = \frac{3}{2}

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{2 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

2 sin^{2} (x) - 5 cos (x) + 1 = 0

sin (a) = \frac{4}{5}

cos (\frac{x}{2}) = 1

8 sin (x) = 4

tan (\frac{x}{2}) = - 3

What is the general solution for 2sin(2θ)=sqrt(3) ?
The general solution for 2sin(2θ)=sqrt(3) is θ= pi/6+pin,θ= pi/3+pin