What is the general solution for cos(θ)=(-1)/2 ?

The general solution for cos(θ)=(-1)/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)=(-1)/2

cos (θ) = \frac{- 1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

cos (θ) = \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

2 sin (x) sec (x) = 2 sin (x)

tan^{3} (x) = tan (x)

3 - 2 sin (x) = 0

- 9 cos^{2} (θ) + 14 sin (θ) + 14 = 0

cos (x) tan (x) = - 7 tan (x)

What is the general solution for cos(θ)=(-1)/2 ?
The general solution for cos(θ)=(-1)/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin