What is the general solution for 6cos(θ)-3=0 ?

The general solution for 6cos(θ)-3=0 is θ= pi/3+2pin,θ=(5pi)/3+2pin

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6cos(θ)-3=0

6 cos (θ) - 3 = 0

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

6 cos (θ) - 3 = 0

Move

3

to the right side

6 cos (θ) = 3

Divide both sides by

6

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

3 cos (θ) + 3 = 2 sin^{2} (θ)

- 33 + 7 csc (\frac{θ}{5} + 2 3^{\circ}) = 53

10 sin (x) tan (x) + tan (x) = 0

2 sin^{2} (θ) + sin (θ) - 1 = 0, 0 \leq θ \leq 2 π

10 sin (x) cos (x) - 7 cos (x) = 0

What is the general solution for 6cos(θ)-3=0 ?
The general solution for 6cos(θ)-3=0 is θ= pi/3+2pin,θ=(5pi)/3+2pin